Power supplied to a particle of mass 2 kg varies with time as P⁡=(3t^2)/2 W, where t is in seconds. If the velocity of the particle at t=0 is v=0…

Question

Power supplied to a particle of mass 2 kg varies with time as P⁡=(3t^2)/2 W, where t is in seconds. If the velocity of the particle at t=0 is v=0, then what is the velocity (in m s^(-1)) of the particle at t=2 s?

MARKS Content Team · Accepted Answer

Correct answer: 2. K_f−K_i=∫P⋅dt 1/2mv^2−0=∫02(3/2t^2)dt 1/2(2)v^2=3/2[t^33]02=4 v=2 ms^(−1)

Power supplied to a particle of mass $2 kg$ varies with time as $P = \frac{3 t^{2}}{2} W$ , where $t$ is in seconds. If the velocity of the particle at $t = 0$ is $v = 0$ , then what is the velocity (in $m s^{- 1}$ ) of the particle at $t = 2 s$ ?

Solution

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Solution

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Power supplied to a particle of mass $2 kg$ varies with time as $P = \frac{3 t^{2}}{2} W$ , where $t$ is in seconds. If the velocity of the particle at $t = 0$ is $v = 0$ , then what is the velocity (in $m s^{- 1}$ ) of the particle at $t = 2 s$ ?