An object of mass 8 kg starts to move from rest under the action of a variable force F=3x N where x is the distance (in m) covered by the object. If…

Question

An object of mass 8 kg starts to move from rest under the action of a variable force F=3x N where x is the distance (in m) covered by the object. If initially, the position of the object is x=2 m, then find its speed (in m s^(-1)) when it crosses x=10 m.

MARKS Content Team · Accepted Answer

Correct answer: 6. Increment in kinetic energy = work done 1/2mv^2-u^2=∫x_1x_2F.dx=∫2103x dx 1/2mv^2=3/2x^2210=3/2100-4 1/2×8×v^2=3/2×96 v=6 m s^(-1)

An object of mass $8 kg$ starts to move from rest under the action of a variable force $F = 3 x N$ where $x$ is the distance (in $m$ ) covered by the object. If initially, the position of the object is $x = 2 m$ , then find its speed (in $m s^{- 1}$ ) when it crosses $x = 10 m$ .

Solution

More Work Power Energy Questions

An object of mass 8 kg starts to move from rest under the action of a variable force F=3x N where x is the distance (in m) covered by the object. If initially, the position of the object is x=2 m, then find its speed (in m s-1) when it crosses x=10 m.

Solution

More Work Power Energy Questions

An object of mass $8 kg$ starts to move from rest under the action of a variable force $F = 3 x N$ where $x$ is the distance (in $m$ ) covered by the object. If initially, the position of the object is $x = 2 m$ , then find its speed (in $m s^{- 1}$ ) when it crosses $x = 10 m$ .