Q6 / 92 · NTA Abhyas (JEE Main) 2020 · Physics · Work Power Energy

A chain (mass M) is hanging from a wooden structure as shown in the figure A. It is slowly taken to a state as shown in the figure B. Calculate the work done by gravity in the process (assume that after reaching the ground, the chain does not form a heap)

Figure

  • A
    Mg 4 a + π b 4 a 2 + b 2 + a b π
  • B
    Mg b 4 a + π b b - a π
  • C
    2 Mg 2 a + π b 4 a 2 - b 2 + ab π
  • Correct answer
    D
    Mg b 4 a + π b b + a π

Solution

Work done by gravity = – (Change in P.E.)

⇒ ui = ulinear + ucurved

= Mass per unit length = M a + π b 4

W gravity = u i - u f = Mgb 4 a + π b b + a π
Figure

Hence, the correct answer is option: 'D'.

More Work Power Energy Questions