Q9 / 92 · NTA Abhyas (JEE Main) 2020 · Physics · Work Power Energy

Power applied to a particle varies with time as P=(3t2-2t+1) watt, where t is in second. What is the change in its kinetic energy (in joule) between t=2 s and t=4 s?

Correct answer: 46

Solution

P=3t2-2t+1=dEdt

∴ dE=(3t2-2t+1)dt

E=∫t=2st=4s(3t2-2t+1)dt

=3t33-2t22+tt=2st=4s

=[43-23-42-22+(4-2)]

E=56-12+2=46 J

Hence, the correct answer is 46.

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