A small object of mass of 100 g moves in a circular path. At a given instant velocity of the object is 10i^ m/s and acceleration is (20i^+10j^) m/s^2…

Question

A small object of mass of 100 g moves in a circular path. At a given instant velocity of the object is 10i^ m/s and acceleration is (20i^+10j^) m/s^2. At this instant of time, rate of change of kinetic energy (in kg m^2 s^(-3)) of the object is

MARKS Content Team · Accepted Answer

Correct answer: 20. Given, mass of object m=100 g =100×10^(-3) kg Velocity of object v=10i^ m/s Acceleration of object a=(20i^+10j^) m/s^2 We know that, (d( KE ))/dt =F.v=ma.v [ ∵K.E.=1/2 mv^2 ] =(100×10^(-3))(20i^+10j^).(10i^) =100×10^(-3)×200 =(100×200)/1000=20 kg m^2/s^3

A small object of mass of $100 g$ moves in a circular path. At a given instant velocity of the object is $10 \hat{i} m/s$ and acceleration is $(20 \hat{i} + 10 \hat{j}) m / s^{2}$ . At this instant of time, rate of change of kinetic energy (in $kg m^{2} s^{- 3}$ ) of the object is

Solution

More Work Power Energy Questions

A small object of mass of 100 g moves in a circular path. At a given instant velocity of the object is 10i^ m/s and acceleration is (20i^+10j^) m/s2. At this instant of time, rate of change of kinetic energy (in kg m2 s-3) of the object is

Solution

More Work Power Energy Questions

A small object of mass of $100 g$ moves in a circular path. At a given instant velocity of the object is $10 \hat{i} m/s$ and acceleration is $(20 \hat{i} + 10 \hat{j}) m / s^{2}$ . At this instant of time, rate of change of kinetic energy (in $kg m^{2} s^{- 3}$ ) of the object is