Q76 / 90 · JEE Main 2024 (09 Apr Shift 2) · Physics
UV light of $4.13 \mathrm{eV}$ is incident on a photosensitive metal surface having work function $3.13 \mathrm{eV}$. The maximum kinetic energy of ejected photoelectrons will be:
- A$4.13 \mathrm{eV}$
- B$3.13 \mathrm{eV}$
- Correct answerC$1 \mathrm{eV}$
- D$7.26 \mathrm{eV}$
Solution
$\begin{aligned} & \mathrm{E}_{\text {photon }}=(\text { work function })+\mathrm{K} \cdot \mathrm{E}_{\max } \\ & \therefore 4.13=3.13+\mathrm{K} \cdot \mathrm{E}_{\max } \\ & \therefore \mathrm{K}_{\mathrm{max}}=1 \mathrm{eV}\end{aligned}$
Hence, the correct answer is option: 'C'.