Q51 / 75 · JEE Main 2026 (04 April Shift 2) · Physics
Match the LIST-I with LIST-II
List-I List-II A. Planck's constant I. $ML^2T^{-2}$ B. Stopping potential II. $T^{-1}$ C. Work function III. $ML^2T^{-1}$ D. Threshold frequency IV. $ML^2T^{-3}A^{-1}$
Choose the correct answer from the options given below:
| List-I | List-II |
|---|---|
| A. Planck's constant | I. $ML^2T^{-2}$ |
| B. Stopping potential | II. $T^{-1}$ |
| C. Work function | III. $ML^2T^{-1}$ |
| D. Threshold frequency | IV. $ML^2T^{-3}A^{-1}$ |
Choose the correct answer from the options given below:
- Correct answerAA-III, B-IV, C-I, D-II
- BA-I, B-II, C-III, D-IV
- CA-IV, B-III, C-I, D-II
- DA-I, B-IV, C-III, D-II
Solution
The dimensional formula for Planck's constant $h$ is obtained from $E = h\nu$.
$[h] = \dfrac{[E]}{[\nu]} = \dfrac{ML^2T^{-2}}{T^{-1}} = ML^2T^{-1}$
The dimensional formula for stopping potential $V_0$ is obtained from $eV_0 = E$.
$[V_0] = \dfrac{[E]}{[e]} = \dfrac{ML^2T^{-2}}{AT} = ML^2T^{-3}A^{-1}$
Work function is a form of energy, so its dimensional formula is the same as that of energy.
$[\text{Work function}] = ML^2T^{-2}$
Threshold frequency has the dimensional formula of frequency.
$[\text{Threshold frequency}] = T^{-1}$
Therefore, the correct matching is A-III, B-IV, C-I, D-II.
Answer: A-III, B-IV, C-I, D-II
$[h] = \dfrac{[E]}{[\nu]} = \dfrac{ML^2T^{-2}}{T^{-1}} = ML^2T^{-1}$
The dimensional formula for stopping potential $V_0$ is obtained from $eV_0 = E$.
$[V_0] = \dfrac{[E]}{[e]} = \dfrac{ML^2T^{-2}}{AT} = ML^2T^{-3}A^{-1}$
Work function is a form of energy, so its dimensional formula is the same as that of energy.
$[\text{Work function}] = ML^2T^{-2}$
Threshold frequency has the dimensional formula of frequency.
$[\text{Threshold frequency}] = T^{-1}$
Therefore, the correct matching is A-III, B-IV, C-I, D-II.
Answer: A-III, B-IV, C-I, D-II
Hence, the correct answer is option: 'A'.