Q80 / 160 · TS EAMCET 2019 (03 May Shift 1) · Mathematics
Two dice are rolled. If a random variable $X$ is defined as the absolute difference of the two numbers that appear on them, then the mean of $X$ is
- A0
- B$\frac{13}{18}$
- C$\frac{19}{9}$
- Correct answerD$\frac{35}{18}$
Solution
Two dice are rolled $X=$ Absolute difference of two number

$$ \begin{aligned} \mu(\text { Mean })=\Sigma P_i X_i & =\frac{0+10+16+18+16+10}{36} \\ & =\frac{70}{36}=\frac{35}{18} \end{aligned} $$

$$ \begin{aligned} \mu(\text { Mean })=\Sigma P_i X_i & =\frac{0+10+16+18+16+10}{36} \\ & =\frac{70}{36}=\frac{35}{18} \end{aligned} $$
Hence, the correct answer is option: 'D'.