Q79 / 160 · TS EAMCET 2025 (03 May Shift 1) · Mathematics
If X is a random variable with probability distribution $\mathrm{P}(\mathrm{X}=k)=\frac{(2 k+3) \mathrm{c}}{3^k}$, $k=0,1,2, \ldots$, to $\infty$, then $\mathrm{P}(\mathrm{X}=3)=$
- A$\frac{1}{24}$
- Correct answerB$\frac{1}{18}$
- C$\frac{1}{6}$
- D$\frac{1}{3}$
Hence, the correct answer is option: 'B'.