Q80 / 160 · TS EAMCET 2025 (03 May Shift 1) · Mathematics
If a Poisson variate $X$ satisfies the relation $P(X=3)=P(X=5)$, then $P(X=4)=$
- Correct answerA$\frac{50}{3 e^{\sqrt{20}}}$
- B$\frac{20000}{3 e^{20}}$
- C$\frac{125}{3 e^{10}}$
- D$\frac{25}{3 e^{\sqrt{20}}}$
Hence, the correct answer is option: 'A'.