Q80 / 160 · TS EAMCET 2025 (04 May Shift 2) · Mathematics
In a Poisson distribution, if $\frac{\mathrm{P}(\mathrm{X}=5)}{\mathrm{P}(\mathrm{X}=2)}=\frac{1}{7500}$ and $\frac{\mathrm{P}(\mathrm{X}=5)}{\mathrm{P}(\mathrm{X}=3)}=\frac{1}{500}$, then the mean of the distribution is
- A$\frac{1}{15}$
- Correct answerB$\frac{1}{5}$
- C$\frac{1}{25}$
- D$\frac{1}{3}$
Hence, the correct answer is option: 'B'.