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Q80 / 160 · TS EAMCET 2025 (04 May Shift 2) · Mathematics

Q9 / 309 · TS EAMCET 2025 (04 May Shift 2) · Mathematics · Probability · Baye's Theorem

In a Poisson distribution, if $\frac{\mathrm{P}(\mathrm{X}=5)}{\mathrm{P}(\mathrm{X}=2)}=\frac{1}{7500}$ and $\frac{\mathrm{P}(\mathrm{X}=5)}{\mathrm{P}(\mathrm{X}=3)}=\frac{1}{500}$, then the mean of the distribution is

  • A
    $\frac{1}{15}$
  • Correct answer
    B
    $\frac{1}{5}$
  • C
    $\frac{1}{25}$
  • D
    $\frac{1}{3}$

Hence, the correct answer is option: 'B'.

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