Q79 / 160 · TS EAMCET 2025 (04 May Shift 1) · Mathematics
The range of a discrete random variable X is $\{1,2,3\}$ and the probabilities of its elements are given by $\mathrm{P}(\mathrm{X}=1)=3 \mathrm{k}^3, \mathrm{P}(\mathrm{X}=2)=2 \mathrm{k}^2$ and $\mathrm{P}(\mathrm{X}=3)=7-19 \mathrm{k}$. Then $\mathrm{P}(\mathrm{X}=3)=$
- Correct answerA$\frac{2}{3}$
- B$\frac{2}{9}$
- C$\frac{1}{9}$
- D$\frac{4}{9}$
Hence, the correct answer is option: 'A'.