Q45 / 92 · NTA Abhyas (JEE Main) 2020 · Physics · Work Power Energy

The velocity-time graph of a particle of mass $10 kg$ is shown in the figure. The net work done on the particle in the first two seconds of the motion is

A
$- 9300 J$
B
$12000 J$
Correct answer
C
$- 4500 J$
D
$- 12000 J$

Solution

v = - 5 t + 50

v_{a t t = 2} = 40

∆ K . E . = W . D . = \frac{1}{2} (40^{2} - 50^{2}) \times 10

= - 4500

J

Hence, the correct answer is option: 'C'.

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