Q9 / 90 · NTA Abhyas (JEE Main) 2020 · Mathematics · Limits

The value of limx→0-⁡43x+1521x21+6x+621x is equal to

Correct answer: 2.5

Solution

limx→0-26x+15⋅21x21+6x+6⋅21x=limx→0-21x25x+1521x225x+6
=limx→0-⁡25x+15225x+6=0+1520+6=156=52

Hence, the correct answer is 2.5.

More Limits Questions