Q10 / 90 · NTA Abhyas (JEE Main) 2020 · Mathematics · Limits

The value of limx→π32-3sin⁡x-cos⁡x3x-π2 is equal to the reciprocal of the number

Correct answer: 9

Solution

limx→π32-232sin⁡x+12cos⁡x3x-π2

⇒limx→π32-2cosx-π33x-π2

Let, x-π3=t

⇒limt→02-2cos⁡t3t2=limt→021-cos⁡t9t2=29⋅12=19

Hence, the correct answer is 9.

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