Q4 / 90 · NTA Abhyas (JEE Main) 2020 · Mathematics · Limits

The value of limx→0+⁡xcot⁡x+xln⁡x is equal to

  • Correct answer
    A
    1
  • B
    2
  • C
    3
  • D
    0

Solution

limx→0+⁡xcot⁡x+limx→0+⁡xln⁡x
=limx→0+⁡xtan⁡x+limx→0+⁡ln⁡x1x
=limx→0+⁡xtan⁡x+limx→0+⁡1x-1x2=1+limx→0+⁡-x
=1+0=1

Hence, the correct answer is option: 'A'.

More Limits Questions