The value of limx→1^(-)(√(π)-√(4tan^(-1)x))/(√(1-x)) is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (D) 0. After rationalization limx→1^(-)(π-4tan^(-1)x)/(√(1-x)√(π)+√(4tan^(-1)x))=1/(2√(π))limx→1^(-)(π-4tan^(-1)x)/(√(1-x)) By L-hospital rule, we get, 1/(2√(π))limx→1^(-)(-4)/(1+x^2)(-1)/(2√(1-x))=4/(√(π))limx→1^(-)(√(1-x))/(1+x^2)=0

The value of $\underset{x \to 1^{-}}{l i m} \frac{\sqrt{π} - \sqrt{4 t a n^{- 1} x}}{\sqrt{1 - x}}$ is equal to

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More Limits Questions

The value of limx→1-π-4tan-1x1-x is equal to

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More Limits Questions

The value of $\underset{x \to 1^{-}}{l i m} \frac{\sqrt{π} - \sqrt{4 t a n^{- 1} x}}{\sqrt{1 - x}}$ is equal to