Q117 / 180 · NEET 2014 · Physics

The number of possible natural oscillations of air column in a pipe closed at one end of length $85 c m$ whose frequencies lies below $1250 H z$ are: (velocity of sound $= 340 {m s}^{- 1}$ )

A
$4$
B
$5$
C
$7$
Correct answer
D
$6$

Solution

Fundamental frequency of a closed organ pipe is $f_{1} = \frac{V}{4 l} = \frac{340}{4 \times 0.85} = 100 H z$
The natural frequencies of the organ pipe will be $f = 100 H z, 300 H z, 500 H z, 700 H z, 900 H z, 1100 H z$ which are below $1250 H z$

Hence, the correct answer is option: 'D'.

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The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lies below 1250 Hz are: (velocity of sound =340 ms-1)

Solution

Relevant Questions

The number of possible natural oscillations of air column in a pipe closed at one end of length $85 c m$ whose frequencies lies below $1250 H z$ are: (velocity of sound $= 340 {m s}^{- 1}$ )