Q116 / 180 · NEET 2014 · Physics

If n1, n2 and n3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:

  • Correct answer
    A
    1n=1n1+1n2+1n3
  • B
    1n=1n1+1n2+1n3
  • C
    n=n1+n2+n3
  • D
    n=n1+n2+n3

Solution

Figure
For first segment we have,

n1=12l1 Tμ

For second segment we have,
n2=12l2 Tμ

For third segment we have,
n3=12l3Tμ

For the whole string we have,
n=12l Tμ

Total length of the string is,
l=l1+l2+l3

Thus, the fundamental frequency for the whole string is,
1n=1n1+1n2+1n3

Hence, the correct answer is option: 'A'.

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