Q119 / 200 · NEET 2023 (All India) · Physics

The ratio of frequencies of fundamental harmonic produced by an open pipe to that of closed pipe having the same length is:

A
$3 : 1$
B
$1 : 2$
Correct answer
C
$2 : 1$
D
$1 : 3$

Solution

Fundamental frequency of open pipe is given by, $f_{o p e n} = \frac{v}{2 l}$ .
Fundamental frequency of closed pipe is given by,
$f_{c l o s e d} = \frac{v}{4 l}$ .
Therefore,
$\frac{f_{o p e n}}{f_{c l o s e d}} = \frac{v}{2 l} \times \frac{4 l}{v} \Rightarrow f_{o p e n} : f_{c l o s e d} = 2 : 1$

Hence, the correct answer is option: 'C'.

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