Q75 / 120 · VITEEE 2017 · Mathematics

The conditional $(p \wedge q) \Rightarrow p$ is

  • Correct answer
    A
    A tautology
  • B
    A fallacy i.e., contradiction
  • C
    Neither tautology nor fallacy
  • D
    None of these

Solution

\begin{array}{|c|c|c|c|} \hlinep & q & p \wedge q & (p \wedge q) \Rightarrow p \\ \hlineT & T & T & T \\ \hlineT & F & F & T \\ \hlineF & T & F & T \\ \hlineF & F & F & T \\ \hline \end{array} $\therefore(p \wedge q) \Rightarrow p$ is a tautology.

Hence, the correct answer is option: 'A'.

Relevant Questions