Q76 / 120 · VITEEE 2019 · Mathematics
The inverse of the statement $(\mathrm{p} \wedge \sim \mathrm{q}) \rightarrow \mathrm{r}$ is
- A$\sim(\mathrm{p} \vee \sim \mathrm{q}) \rightarrow \sim \mathrm{r}$
- B$(\sim \mathrm{p} \wedge \mathrm{q}) \rightarrow \sim \mathrm{r}$
- Correct answerC$(\sim \mathrm{p} \vee \mathrm{q}) \rightarrow \sim \mathrm{r}$
- DNone of these
Solution
The inverse of the proposition $(\mathrm{p} \wedge \sim \mathrm{q})$ $\rightarrow \mathrm{r}$ is
$$
\begin{aligned}
\sim(\mathrm{p} \wedge \sim \mathrm{q}) \rightarrow \sim \mathrm{r} \equiv \sim \mathrm{p} \vee \sim(\sim \mathrm{q}) & \rightarrow \sim \mathrm{r} \\
& \equiv \sim \mathrm{p} \vee \mathrm{q} \rightarrow \sim \mathrm{r}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.