Q38 / 120 · JEE Advanced 2006 · Chemistry
Match the following
- Correct answerA(A) Q,S, (B) S, (C) R, (D) Q,R
- B(A) Q,S, (B) R, (C) S, (D) Q
- C(A) P,R, (B) P, R, (C) R, (D) Q,R
- D(A) P,R, (B) P, (C) R, (D) Q,R
Solution
A match with $\boldsymbol{Q}, \boldsymbol{S} \quad \mathrm{Bi}^{3+}+\mathrm{H}_2 \mathrm{O} \longrightarrow[\mathrm{BiO}]^{+}+2 \mathrm{H}^{+}$ B match with $\boldsymbol{S} \mathrm{NaAlO}_2+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Al}(\mathrm{OH})_3+\mathrm{NaOH}$ C match with $\boldsymbol{R} \quad 2 \mathrm{SiO}_4^{4-}+2 \mathrm{H}^{+} \longrightarrow \mathrm{Si}_2 \mathrm{O}_7^{6-}+\mathrm{H}_2 \mathrm{O}$ Pyrosilicate is formed by treating orthosilicate with acid. D match with $\boldsymbol{Q}, \boldsymbol{R} \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \underset{\text { or } \mathrm{H}_2 \mathrm{SO}_4}{\stackrel{\mathrm{HCl}}{\mathrm{O}_3}} \mathrm{H}_3 \mathrm{BO}_3$
$$
\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_4 \stackrel{\mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{H}_3 \mathrm{BO}_3
$$
Hence, the correct answer is option: 'A'.