In a solid AB,A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the…

Question

In a solid AB,A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is A_xB_y. The value of x is [nearest integer]

MARKS Content Team · Accepted Answer

Correct answer: 3. A forms ccp structure that means number of A atoms per unit cell →4 B atoms per unit cell →4 (Octahedral voids), as number of octahedral voids will be equal to number of atoms per unit cell. A removed =2×1/2=1 A left =4-1=3 Formula becomes A_3B_4 x=3.

In a solid $AB, A$ atoms are in $ccp$ arrangement and $B$ atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is $A_{x} B_{y}$ . The value of $x$ is [nearest integer]

Solution

Relevant Questions

In a solid AB,A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is AxBy. The value of x is [nearest integer]

Solution

Relevant Questions

In a solid $AB, A$ atoms are in $ccp$ arrangement and $B$ atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is $A_{x} B_{y}$ . The value of $x$ is [nearest integer]