An atomic substance A of molar mass 12 g mol^(–1) has a cubic crystal structure with edge length of 300 pm. The no. of atoms present in one unit cell…

Question

An atomic substance A of molar mass 12 g mol^(–1) has a cubic crystal structure with edge length of 300 pm. The no. of atoms present in one unit cell of A is (Nearest integer) Given the density of A is 3.0 g m m^(-1) and NA_A=6.02×10^23 mol^(-1)

MARKS Content Team · Accepted Answer

Correct answer: 4. The density of crystal can be calculated as follows, ρ=(Z×M)/(N_A×a^3) ρ=density of the unit cell Z=Effective atomic number M=Molar mass N_A=Avogadro's number a=Edge length of the unit cell 3=(Z×12)/(6.02×10^23×(3)^3×10^(-24)) Z=(6.02×10^(-1)×27)/4=4

An atomic substance A of molar mass $12 g {mol}^{- 1}$ has a cubic crystal structure with edge length of $300 pm$ . The no. of atoms present in one unit cell of A is
(Nearest integer)
Given the density of A is $3.0 g m m^{- 1}$ and ${NA}_{A} = 6.02 \times 10^{23} {mol}^{- 1}$

Solution

Relevant Questions

An atomic substance A of molar mass 12 g mol–1 has a cubic crystal structure with edge length of 300 pm. The no. of atoms present in one unit cell of A is(Nearest integer)Given the density of A is 3.0 g m m-1 and NAA=6.02×1023 mol-1

Solution

Relevant Questions

An atomic substance A of molar mass $12 g {mol}^{- 1}$ has a cubic crystal structure with edge length of $300 pm$ . The no. of atoms present in one unit cell of A is
(Nearest integer)
Given the density of A is $3.0 g m m^{- 1}$ and ${NA}_{A} = 6.02 \times 10^{23} {mol}^{- 1}$