A metal M crystallizes into two lattices :- face centred cubic (fcc) and body centred cubic (bcc) with unit cell edge length of 2.0 and 2.5A°…

Question

A metal M crystallizes into two lattices :- face centred cubic (fcc) and body centred cubic (bcc) with unit cell edge length of 2.0 and 2.5A° respectively. The ratio of densities of lattices fcc to bec for the metal M is _______(Nearest integer)

MARKS Content Team · Accepted Answer

Correct answer: 4. The density of the crystal lattice can be calculated as follows, d=(Z×M)/(N_Aa^3) Z=effective number of atoms in unit cell(For BCC=2 and FCC=4) M=Molar mass N_A=Avogadro's number a=Edge length d_FCCd_BCC=(4×M_wN_A×(2)^3)/(2×M_wN_A×(2.5)^3)=3.90

A metal M crystallizes into two lattices :- face centred cubic (fcc) and body centred cubic (bcc) with unit cell edge length of $2.0$ and $2.5 \overset{°}{A}$ respectively. The ratio of densities of lattices fcc to bec for the metal M is _______(Nearest integer)

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