Q85 / 90 · JEE Main 2024 (30 Jan Shift 2) · Physics

If the total energy transferred to a surface in time t is 6.48×105 J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :

  • A
    2.46×10-3 kg m s-1
  • Correct answer
    B
    2.16×10-3 kg m s-1
  • C
    1.58×10-3 kg m s-1
  • D
    4.32×10-3 kg m s-1

Solution

As we know,

p=Ec, where c is velocity of light.

Therefore, p=6.48×1053×108=2.16×10-3 kg m s-1

Hence, the correct answer is option: 'B'.

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