Q141 / 180 · NEET 2014 · Physics

If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is:

  • A
    25
  • Correct answer
    B
    75
  • C
    60
  • D
    50

Solution

KEfinal=16KEinitial

⇒12mvf2=16×12mvi2(mass remains same because the particle remains same)

⇒vf=4vi
We know that, De-broglie wavelength (λ)=hmv

∴λf=hmvf=h4mvi

  So De-Broglie wave will decreased to 75%

Hence, the correct answer is option: 'B'.

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