Q129 / 180 · NEET 2020 (Phase 1) · Physics

An electron is accelerated from rest through a potential difference of $V$ volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{- 2} nm$ , the potential difference is:

Solution

$λ = 1.227 \times 10^{- 2} nm$

$= 0.1227 Å$

$λ = \frac{12.27}{\sqrt{v}} Å$

$0.227 = \frac{12.27}{\sqrt{v}} Å$

$\sqrt{v} = 10^{2} \Rightarrow v = 10^{4}$ volt

Hence, the correct answer is option: 'C'.