Q128 / 180 · NEET 2020 (Phase 1) · Physics

A screw gauge has least count of $0.01 mm$ and there are $50$ divisions in its circular scale. The pitch of the screw gauge is:

A
$0 .25 mm$
Correct answer
B
$0 .5 mm$
C
$1 .0 mm$
D
$0 .01 mm$

Solution

The least count on screw gauge is given by, $L.C. = \frac{Pitch}{Number of division on circular scale}$

$\Rightarrow 0.01 mm = \frac{Pitch}{50}$

$\Rightarrow Pitch = 0.5 mm$

Hence, the correct answer is option: 'B'.

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