Q16 / 150 · MHT CET 2026 (17 April Shift 1) · Chemistry
Alkenes on oxidation with $\text{KMnO}_4$ in dil $\text{H}_2\text{SO}_4$ forms
- AAlkanol
- BAlkanal
- CAlkanone
- Correct answerDAlkanoic acid
Solution
Alkenes undergo oxidative cleavage when treated with a strong oxidizing agent like $\text{KMnO}_4$ in acidic medium (dilute $\text{H}_2\text{SO}_4$).
During this reaction, the carbon-carbon double bond is completely cleaved. A $=\text{CH}-$ group is initially oxidized to an aldehyde (alkanal), which is highly susceptible to further oxidation under these conditions and immediately oxidizes to a carboxylic acid (alkanoic acid).
For example:
$\text{R}-\text{CH}=\text{CH}-\text{R}' \xrightarrow{\text{KMnO}_4 / \text{H}^+} \text{R}-\text{COOH} + \text{R}'-\text{COOH}$
Thus, the final stable product formed is an alkanoic acid.
Answer: Alkanoic acid
During this reaction, the carbon-carbon double bond is completely cleaved. A $=\text{CH}-$ group is initially oxidized to an aldehyde (alkanal), which is highly susceptible to further oxidation under these conditions and immediately oxidizes to a carboxylic acid (alkanoic acid).
For example:
$\text{R}-\text{CH}=\text{CH}-\text{R}' \xrightarrow{\text{KMnO}_4 / \text{H}^+} \text{R}-\text{COOH} + \text{R}'-\text{COOH}$
Thus, the final stable product formed is an alkanoic acid.
Answer: Alkanoic acid
Hence, the correct answer is option: 'D'.