Q37 / 150 · MHT CET 2026 (15 April Shift 1) · Chemistry
Which one of the following compound will show addition of HBr to alkene according to markownikoff's rule?
- ABut-2-ene
- BHex-3-ene
- CEthene
- Correct answerD2-methyl propene
Solution
Markovnikov's rule is applicable for the addition of unsymmetrical reagents to unsymmetrical alkenes.
But-2-ene ($CH_3-CH=CH-CH_3$) is a symmetrical alkene.
Hex-3-ene ($CH_3-CH_2-CH=CH-CH_2-CH_3$) is a symmetrical alkene.
Ethene ($CH_2=CH_2$) is a symmetrical alkene.
2-methylpropene ($CH_3-C(CH_3)=CH_2$) is an unsymmetrical alkene.
Therefore, 2-methylpropene will undergo addition of HBr according to Markovnikov's rule.
But-2-ene ($CH_3-CH=CH-CH_3$) is a symmetrical alkene.
Hex-3-ene ($CH_3-CH_2-CH=CH-CH_2-CH_3$) is a symmetrical alkene.
Ethene ($CH_2=CH_2$) is a symmetrical alkene.
2-methylpropene ($CH_3-C(CH_3)=CH_2$) is an unsymmetrical alkene.
Therefore, 2-methylpropene will undergo addition of HBr according to Markovnikov's rule.
Hence, the correct answer is option: 'D'.