A uniform chain of length $L$ and mass $M$ overhangs a horizontal table with its two-third part on the table. The friction coefficient between the table and the chain is $\mu$. The work done by friction during the period, the chain slips of the table is

• Correct answer
  A

  $-\frac{2}{9}\mu MgL$
• B

  $-\frac{6}{9}\mu MgL$
• C

  $-\frac{1}{4}\mu MgL$
• D

  $-\frac{4}{9}\mu MgL$

Hence, the correct answer is option: 'A'.