Q130 / 200 · NEET 2024 · Physics
A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V ) shown in the figure is:
(Take $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9$ SI units)
- A$1 \times 10^5$
- B$0.5 \times 10^5$
- Correct answerCZero
- D$3 \times 10^5$
Solution
For uniformly charged spherical shell,
$\begin{aligned}
& V=\frac{k q}{R} \quad(\text { For } r \leq R) \\
& \therefore \quad V_C=V_P \\
& \\
& V_C-V_P=\text { Zero }
\end{aligned}$
Hence, the correct answer is option: 'C'.