The value of electric potential at a distance of 9 cm from the point charge $4 \times 10^{-7} \mathrm{C}$ is $\left[\right.$ Given $\left.\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 \mathrm{C}^{-2}\right]$ :

• A

  $4 \times 10^2 V$
• B

  44.4 V
• C

  $4.4 \times 10^5 \mathrm{~V}$
• Correct answer
  D

  $4 \times 10^4 \mathrm{~V}$

Hence, the correct answer is option: 'D'.