Q113 / 200 · NEET 2021 · Physics

Two charged spherical conductors of radius $R_{1}$ and $R_{2}$ are connected by a wire. Then the ratio of surface charge densities of the spheres $(σ_{1} / σ_{2})$ is :

Solution

$V_{1} = V_{2}$

$\frac{k q_{1}}{R_{1}} = \frac{k q_{2}}{R_{2}}$

$\frac{σ_{1} 4 π {(R_{1})}^{2}}{R_{1}} = \frac{σ_{2} 4 π {(R_{2})}^{2}}{R_{2}}$

$\frac{σ_{1}}{σ_{2}} = \frac{R_{2}}{R_{1}}$

Hence, the correct answer is option: 'B'.