Q49 / 92 · NTA Abhyas (JEE Main) 2020 · Physics · Work Power Energy

A massless string and a spring connect two blocks A and B to each other. Block B slides over a frictionless inclined plane while block A slides over horizontal surface. Coefficient of friction between block A horizontal surface is μ=0.2.At the instant shown blocks are moving with constant speed. Mass of block A and energy stored in spring are respectively. [ g=10  m/ s 2  ,  m B =2 kg ]

Figure

  • A
    5 kg, 1J
  • B
    10 kg, 0.05 J
  • Correct answer
    C
    5 kg, 0.05 J
  • D
    10 kg, 1J

Solution

2 g sin θ=kx =μ mA g

⇒    m A = 2 g  sin θ μ g = 2 sin θ μ = 2 × 1 2 0 . 2 = 5 kg

kx = 2 × 1 0 × 1 2 = 1 0

x = 1 0 1 × 1 0 3 = 1  cm

⇒    Energy = 1 2 × 1 0 3 × 1 0 - 2 2 = 0 . 0 5  Joule

Hence, the correct answer is option: 'C'.

More Work Power Energy Questions