Q48 / 120 · VITEEE 2011 · Mathematics
A line passes through $(2,2)$ and is perpendicular to the line $3 x+y=3$. What is its $y$-intercept?
- A$1 / 3$
- B$2 / 3$
- C1
- Correct answerD$4 / 3$
Solution
Equation of line perpendicular to $3 x+y-3=0$ is $x-3 y+c=0$
Since, it passes through $(2,2)$
$$
\therefore \mathrm{c}=4
$$
$\therefore$ Equation of line perpendicular to $3 x+y-3=0$ is $x-3 y+4=0$
For $y$ - intercept, put $x=0$
$$
\therefore y=\frac{4}{3}
$$
Hence, the correct answer is option: 'D'.