Q61 / 120 · VITEEE 2012 · Mathematics

A straight line through the point $\mathrm{A}(3,4)$ is such that its intercept between the axes is bisected at A, its equation is

  • A
    $3 x-4 y+7=0$
  • Correct answer
    B
    $4 x+3 y=24$
  • C
    $3 x+4 y=25$
  • D
    $x+y=7$

Solution

A is mid point of line PQ. $$ \therefore 3=\frac{\mathrm{a}+0}{2} \Rightarrow \mathrm{a}=6 $$ and $4=\frac{0+b}{2} \Rightarrow b=8$ Figure
Thus, equation of line is $$ \begin{array}{l} \frac{x}{6}+\frac{y}{8}=1 \\ \Rightarrow 4 x+3 y=24 \end{array} $$

Hence, the correct answer is option: 'B'.

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