Q61 / 120 · VITEEE 2012 · Mathematics
A straight line through the point $\mathrm{A}(3,4)$ is such that its intercept between the axes is bisected at A, its equation is
- A$3 x-4 y+7=0$
- Correct answerB$4 x+3 y=24$
- C$3 x+4 y=25$
- D$x+y=7$
Solution
A is mid point of line PQ.
$$
\therefore 3=\frac{\mathrm{a}+0}{2} \Rightarrow \mathrm{a}=6
$$
and $4=\frac{0+b}{2} \Rightarrow b=8$

Thus, equation of line is $$ \begin{array}{l} \frac{x}{6}+\frac{y}{8}=1 \\ \Rightarrow 4 x+3 y=24 \end{array} $$

Thus, equation of line is $$ \begin{array}{l} \frac{x}{6}+\frac{y}{8}=1 \\ \Rightarrow 4 x+3 y=24 \end{array} $$
Hence, the correct answer is option: 'B'.