Q40 / 110 · VITEEE 2024 · Mathematics
In a triangle $A B C$ as shown in the diagram, where $A B=5, A C=10$ and $B D=1$, then perimeter of $\triangle A B C$ is


- A9
- Correct answerB18
- C20
- D30
Solution
$\because A D$ divides $\angle B A C$ is two equal parts.
So, by angle bisector formula
$\begin{aligned}
& \frac{B D}{D C}=\frac{A B}{A C} \Rightarrow \frac{1}{D C}=\frac{5}{10} \\
\Rightarrow \quad & D C=2
\end{aligned}$
Therefore, $B C=B D+D C=1+2=3$
Hence, perimeter of $\triangle A B C=A B+B C+C A$
$=5+3+10=18$
Hence, the correct answer is option: 'B'.