Q23 / 125 · BITSAT 2013 · Chemistry

A current of 2.0 A passed for 5 hours through a molten metal salt deposits $22.2 \mathrm{~g}$ of metal (At wt. $=177$ ). The oxidation state of the metal in the metal salt is

  • A
    1
  • B
    2
  • Correct answer
    C
    3
  • D
    4

Solution

$\mathrm{m}=\frac{\mathrm{E} \cdot \mathrm{wt} \times \mathrm{Q}}{96500}$ $\begin{aligned} \therefore \mathrm{E} . \mathrm{wt} &=\frac{\mathrm{m} \times 96500}{\mathrm{Q}} \\=\frac{22.2 \times 96500}{2 \times 5 \times 60 \times 60}=60.3 \end{aligned}$ Oxidation state $=\frac{\text { At wt. }}{\text { Eq. wt. }}=\frac{177}{60.3}=3$

Hence, the correct answer is option: 'C'.

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