Q24 / 100 · BITSAT 2023 (Memory Based Paper 2) · Chemistry
Given that $E_{\mathrm{O}_2 / \mathrm{H}_2 \mathrm{O}}^{\circ}=+1.23 \mathrm{~V}$;
$\begin{aligned}<br />& E_{\mathrm{S}_2 \mathrm{O}_8^{2-} / \mathrm{SO}_4^{2-}}^{\circ}=2.05 \mathrm{~V} ; E_{\mathrm{Br}_2 / \mathrm{Br}^{-}}^{\circ}=+1.09 \mathrm{~V} \\<br />& E_{\mathrm{Au}^{3+} / \mathrm{Au}}^{\circ}=+1.4 \mathrm{~V}<br />\end{aligned}$
The strongest oxidising agent is :
$\begin{aligned}<br />& E_{\mathrm{S}_2 \mathrm{O}_8^{2-} / \mathrm{SO}_4^{2-}}^{\circ}=2.05 \mathrm{~V} ; E_{\mathrm{Br}_2 / \mathrm{Br}^{-}}^{\circ}=+1.09 \mathrm{~V} \\<br />& E_{\mathrm{Au}^{3+} / \mathrm{Au}}^{\circ}=+1.4 \mathrm{~V}<br />\end{aligned}$
The strongest oxidising agent is :
- A$\mathrm{Au}^{3+}$
- B$\mathrm{O}_2$
- Correct answerC$\mathrm{S}_2 \mathrm{O}_8^{2-}$
- D$\mathrm{Br}_2$
Solution
Reduction potential is maximum for $\mathrm{S}_2 \mathrm{O}_8{ }^{2-}$ therefore, it is the strongest oxidising agent amongst the given species.
Hence, the correct answer is option: 'C'.