Q22 / 125 · BITSAT 2013 · Chemistry

Equal weights of $\mathrm{NaCl}$ and $\mathrm{KCl}$ are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

  • A
    Equal
  • B
    That of $\mathrm{NaCl}$ will be less than that of $\mathrm{KCl}$
  • Correct answer
    C
    That of $\mathrm{NaCl}$ will be more than that of $\mathrm{KCl}$ solution
  • D
    That of $\mathrm{NaCl}$ will be about half of that of $\mathrm{KCl}$ solution

Solution

When equal weights of different solutes are present in equal volumes of solution the molarity is inversely related to molecular mass of the solute. Mol. mass of $\mathrm{NaCl}$ is less than $\mathrm{KCl}$. Hence, molarity of $\mathrm{NaCl}$ solution will be more.

Hence, the correct answer is option: 'C'.

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