Mathematics - Permutation Combination
Practise 235 AP EAMCET previous year questions on Permutation Combination, compiled from papers spanning 2001 to 2025. Each question is pulled directly from the actual exam paper it appeared in, so you're practising in the exact style and difficulty AP EAMCET tests.
Permutation Combination has been asked in 23 of the 24 years of AP EAMCET papers analysed (2001–2024), with 235 questions in all. 48% of them were easy, 46% moderate and 6% tough. Most of its questions came from 2022, with 31 questions that year. In the last three years (2022–2024) it had 71 questions across 28 papers, about 2.5 per paper.
The chapter's 12 topics are not weighted equally: Permutation (58 questions, 25%), Combination (49 questions, 21%), and Arrangement under Constraint (42 questions, 18%) have been asked the most. Permutation has also led over the last five years, with 31 questions. Permutation has produced the most tough questions (6).
- 1An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this27 May, 2025 (M)Permutation
- 2A string of letters is to be formed by using 4 letters from all the letters of the word "MATHEMATICS". The number of ways this can be done s27 May, 2025 (M)Permutation
- 3The number of positive integers less than 10000 which contain the digit 5 atleast once is26 May, 2025 (M)Permutation
- 45 men and 4 women are seated in a row. If the number of arragements in which one particular man and one particular woman are together is ' '26 May, 2025 (M)Arrangement under Constraint
- 5If a team of 4 persons is to be selected out of 4 married couples to play mixed doubles tennis game, then the number of ways of forming a te26 May, 2025 (M)Permutation
- 6All possible words (with or without meaning) are formed by taking atleast 2 letters (all different) from the letters of the word 'CURVE'. If26 May, 2025 (M)Permutation
- 7The number of integers greater than 6000 that can be formed by using the digits and 9 without repetition is26 May, 2025 (E)Permutation
- 8The number of ways of dividing 15 persons into 3 groups containing 3,5 and 7 persons so that two particular persons are not included into th26 May, 2025 (E)Combination
- 9A company representative is distributing 5 identical samples of a product among 12 houses in a row such that each house gets at most one sam26 May, 2025 (E)Arrangement under Constraint
- 10The number of integers between 10 and 10,000 such that in every integer every digit is greater than its immediate preceeding digit, is24 May, 2025 (M)Combination
- 11All letters of the word 'AGAIN' are permuted in all possible ways and the words so formed (with or without meaning) are written as in a dict24 May, 2025 (M)Permutation
- 12The number of ways in which a cricket team of 11 members can be formed out of 6 batsmen, 6 bowlers, 4 all-rounders and 4 wicket keepers by s24 May, 2025 (M)Combination
- 13If 3 sisters and 8 brothers are together playing a game, then the number of ways in which all the sisters and brothers are to be seated arou23 May, 2025 (M)Arrangement under Constraint
- 14Out of 8 students in a classroom, 4 of them are chosen and they are arranged around a table. If the remaining 4 are arranged in a row, then 23 May, 2025 (M)Permutation
- 15If all possible 4 digit numbers are formed by choosing 4 different digits from the given digits then, the sum of all such 4 digit numbers is23 May, 2025 (E)Permutation
- 16The number of ways of forming the ordered pairs ( ) such that by choosing p and q from the first 50 natural numbers is23 May, 2025 (E)Combination
- 17The number of ways in which a committee of 7 members can be formed from 6 teachers, 5 fathers and 4 students in such a way that at least one23 May, 2025 (E)Combination
- 18All the letters of the word LETTER are arranged in all possible ways and the words (with or without meaning) thus formed are arranged in dic22 May, 2025 (M)Permutation
- 195 digit numbers are formed by using the digits without repetetion and all of them are arranged in ascending order. Then the rank of the numb22 May, 2025 (M)Permutation
- 20The number of divisors of is22 May, 2025 (M)Selection of one or more item
- 21If , then22 May, 2025 (E)Permutation
- 22If the number of diagonals of a regular polygon is 35, then the number of sides of the polygon is22 May, 2025 (E)Permutation
- 23If four letters are chosen from the letters of the word ASSIGNMENT and are arranged in all possible ways to form 4 letter words (with or wit22 May, 2025 (E)Permutation
- 24The number of all possible positive integral solutions of the equation is21 May, 2025 (M)Division of Identical items
- 25The number of all five letter words (with or without meaning) having atleast one repeated letter that can be formed by using the letters of 21 May, 2025 (M)Permutation
- 26The number of ways of arranging all the letters of the word PERFECTION such that there must be exactly two consonants between any two vowels21 May, 2025 (M)Permutation
- 27If all the letters of the word COMBINATION are arranged in all possible ways to form 11 letter words (with or without meaning), then the num21 May, 2025 (E)Permutation
- 28The number of ways of distributing 3 dozen fruits (no two fruits are identical) to 9 persons such that each gets the same number of fruits i21 May, 2025 (E)Permutation
- 29Among the 4 digit numbers formed using the digits when repetition of digits allowed, the number of numbers which are divisible by 4 is23 May, 2024 (M)Permutation
- 30The number of ways of arranging 2 red. 3 white and 5 yellow roses of different sizes into a garland such that no two yellow roses come toget23 May, 2024 (M)Circular Permutation
- 31All the letters of the word TABLE are permuted and the strings of letters (may or may not have meaning) thus formed are arranged in dietiona22 May, 2024 (M)Arrangement under Constraint
- 325 boys and 6 girls are arranged in all possible ways. Let X denote the number of linear arrangements in which no two boys sit together and d22 May, 2024 (M)Arrangement under Constraint
- 33The number of ways of distributing 15 apples to three persons such that A and C each get at least 2 apples and B gets at most 5 apples is22 May, 2024 (M)Division of Identical items
- 34There are two women participating with some men in a chess tournament. Each participant played two games with the other. The number of games22 May, 2024 (E)Combination
- 35The number of ways of arranging 9 men and 5 women around a circular table so that no two women come together are22 May, 2024 (E)Circular Permutation
- 36If there are 6 alike fruits, 7 alike vegetables and 8 alike biscuits, then the number of ways of selecting any number of things out of them 22 May, 2024 (E)Selection of one or more item
- 37The number of 5 digit odd numbers greater than 40,000 that can be formed by using so that at least one of its digit must be repeated is21 May, 2024 (M)Arrangement under Constraint
- 38The number of ways in which 3 men and 3 women can be arranged in a row of 6 seats, such that the first and last seats must be filled by men 21 May, 2024 (M)Arrangement under Constraint
- 39If a committee of 10 members is to be formed from 8 men and 6 women, then the number of different possible committees in which the men are i21 May, 2024 (M)Arrangement under Constraint
- 40There are 6 different novels and 3 different poetry books on a table. If 4 novels and 1 poetry book are to be selected and arranged in a row21 May, 2024 (E)Permutation
- 41If a five digit number divisible by 3 is to be formed using the numbers and 5 without repetition, then the total number of ways this can be 21 May, 2024 (E)Arrangement under Constraint
- 42Four digit numbers with all digits distinct are formed using the digits in all possible ways. If is the total number of numbers thus formed 21 May, 2024 (E)Permutation
- 43If a polygon of sides has 275 diagonals. then is20 May, 2024 (M)Selection of one or more item
- 44The number of positive divisors of 1080 is20 May, 2024 (M)Selection of one or more item
- 45A test containing 3 objective type of questions is conducted in a class. Each question has 4 options and only one option is the correct answ20 May, 2024 (E)Arrangement under Constraint
- 46The number of numbers lying between 1000 and 10000 such that every number contains the digits 3 and 7 only once without repetition is20 May, 2024 (E)Permutation
- 47The number of ways in which 17 apples can be distributed among four guests such that each guest gets at least 3 apples is20 May, 2024 (E)Selection of one or more item
- 48If all the letters of the word MASTER are permuted in all possible ways and words (with or without meaning) thus formed are arranged in dict19 May, 2024 (E)Permutation
- 49The number of different permutations that can be formed by taking 4 letters at a time from the letters of the word 'REPETITION' is19 May, 2024 (E)Permutation
- 50The number of different ways of preparing a garland by using 6 distinct white roses and 6 distinct red roses such that no two red roses come18 May, 2024 (M)Circular Permutation
Frequently Asked Questions
1.How many questions are available for Permutation Combination?
This chapter includes 235 questions compiled from AP EAMCET papers spanning 2001 to 2025.
2.Are these questions only from AP EAMCET, or from other exams too?
These are AP EAMCET questions specifically for the Permutation Combination chapter. Questions from other exams like JEE Main or NTA Abhyas (JEE Main) are organised separately under their respective exam sections.
3.Is Permutation Combination an important chapter for AP EAMCET Mathematics?
Permutation Combination has appeared in 24 of the 25 years of AP EAMCET papers covered here, with 235 questions across 92 papers - about 3 per paper it appears in.
4.What is the difficulty level of Permutation Combination questions in AP EAMCET?
Of the 235 questions analysed for this chapter, 48% are easy, 46% moderate and 6% tough. 2022 had the most, with 31 questions.
5.Which topics in Permutation Combination should I focus on?
These topics have carried the most weightage in Permutation Combination:
- Permutation - 58 questions (25%)
- Combination - 49 questions (21%)
- Arrangement under Constraint - 42 questions (18%)
- Permutation has produced the most tough questions (6).
6.Is Permutation Combination's weightage in AP EAMCET going up or down?
Across all 92 papers analysed, Permutation Combination has averaged about 2.6 questions per paper. In the last three years (2022–2024), that average has stayed about the same, at about 2.5 questions per paper. Use the year-wise numbers on this page for the exact trend before you decide how much time to give it.