Q55 / 160 · AP EAMCET 2025 (21 MAY SHIFT 2) · Mathematics

The number of ways of distributing 3 dozen fruits (no two fruits are identical) to 9 persons such that each gets the same number of fruits is

A
$\frac{36!}{(9!)^4}$
Correct answer
B
$\frac{36!}{(4!)^9}$
C
${ }^{36} \mathrm{P}_9 \times 4!$
D
$\frac{36!}{4!(9!)^4}$

Hence, the correct answer is option: 'B'.

Relevant Questions

An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this27 May, 2025 (M)Permutation
A string of letters is to be formed by using 4 letters from all the letters of the word "MATHEMATICS". The number of ways this can be done s27 May, 2025 (M)Permutation
The number of positive integers less than 10000 which contain the digit 5 atleast once is26 May, 2025 (M)Permutation
If a team of 4 persons is to be selected out of 4 married couples to play mixed doubles tennis game, then the number of ways of forming a te26 May, 2025 (M)Permutation
All possible words (with or without meaning) are formed by taking atleast 2 letters (all different) from the letters of the word 'CURVE'. If26 May, 2025 (M)Permutation
The number of integers greater than 6000 that can be formed by using the digits and 9 without repetition is26 May, 2025 (E)Permutation