Which plot of $\ln k$ vs $\frac{1}{\mathrm{~T}}$ is consistent with Arrhenius equation?

• A

  
  
• B

  
  
• Correct answer
  C

  
  
• D

  
  

Solution

The Arrhenius equation is given as $\begin{aligned} & k=A e^{-\frac{E_a}{R T}} \\ & \therefore \quad \ln k=\ln A-\frac{E_a}{R T} \end{aligned}$ In $\mathrm{k} v / \mathrm{s} \frac{1}{\mathrm{~T}}$ gives a straight line graph with slope $=-\frac{E_{\mathrm{a}}}{R}$ and intercept $=\ln \mathrm{A}$

Hence, the correct answer is option: 'C'.