When $200 \mathrm{mL}$ of $0.2 \mathrm{M}$ acetic acid is shaken with $0.6 \mathrm{g}$ of wood charcoal, the final concentration of acetic acid after adsorption is $0.1 \mathrm{M}$. The mass of acetic acid adsorbed per gram of carbon is $\mathrm{g}$.

Mole of acetic acid absorbed (on 0.6 gram charcoal) $$\begin{gathered} =(0.2 \mathrm{X}200){10}^{-3} – (0.1 \mathrm{X} 200){10}^{-3} \\ =20 X {10}^{-3} \end{gathered}$$

Weight of CH₃COOH absorbed (on 0.6 gram charcoal)$=(20 \mathrm{X}{10}^{-3} ) 60 = 1200 \mathrm{X}{10}^{-3} \mathrm{gram} = 1.2 \mathrm{gram}$

Mass of CH₃COOH absorbed per gram=$\frac{1.2}{0.6}=2$grams