Q16 / 90 · JEE Main 2023 (31 Jan Shift 2) · Chemistry

Match List I with List II

List I List II
A Physisorption I Single Layer Adsorption
B Chemisorption II 20-40 kJ mol-1
C N2g+3H2g⟶Fe(s)2NH3g III Chromatography
D Analytical Application or Adsorption IV Heterogeneous catalysis

Choose the correct answer from the options given below:

  • A
    A-III, B-IV, C-I, D-II
  • B
    A-II, B-III, C-I, D-IV
  • Correct answer
    C
    A-II, B-I, C-IV, D-III
  • D
    A-IV, B-II, C-III, D-I

Solution

(A) In physisorption, the enthalpy heat is low and lies between 20 - 40 kJ mol-1. In physisorption, multilayers of adsorbed particles are formed.

(B) In chemisorption, the enthalpy heat is high and lies within the range of 40 - 200 kJ mol-1.  In chemisorption, a monolayer of adsorbed particles is formed.

(C) N2g+3H2g⟶Fe(s)2NH3g

Heterogeneous catalysts occupy a different phase. Generally, heterogeneous catalysts are solid compounds that are added to liquid or gas reaction mixtures. Fe is used as a heterogeneous catalyst in the Haber process.

(D) In the process of adsorption chromatography, different compounds are adsorbed on the adsorbent to different degrees based on the absorptivity of the component. 

So, the correct matching is A-IV, B-II, C-III, D-I.

 

Hence, the correct answer is option: 'C'.

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