Q25 / 90 · JEE Main 2022 (26 Jun Shift 1) · Chemistry

$2.0 g$ of $H_{2} gas$ is adsorbed on $2.5 g$ of platinum powder at $300 K$ and $1$ bar pressure. The volume of the gas adsorbed per gram of the adsorbent is $mL$
(Given : $R = 0.083 L$ bar $K^{- 1} {mol}^{- 1}$ )

Correct answer: 9960

Solution

$V_{H_{2}} = \frac{nRT}{P} V_{H_{2}} (g) = (\frac{2}{2}) \frac{(0.083) 300}{1}$

$∴$ Volume of $H_{2} (g)$ adsorbed on $2.5 Pt = 24.9 L$

$∴$ Volume of $H_{2} (g)$ adsorbed on $1 g of Pt = \frac{24.9}{2.5} = 9.96 L = 9960 ml$

Hence, the correct answer is 9960.