Q48 / 150 · MHT CET 2026 (18 April Shift 2) · Chemistry
What is the number of moles of hydrogen atoms needed to obtain one mole ethanamine from acetamide using $\text{LiAl H}_4$ /ether as reducing agent.
- Correct answerA$4$
- B$3$
- C$2$
- D$1$
Solution
The chemical reaction for the reduction of acetamide to ethanamine using $\text{LiAlH}_4$ is:
$\text{CH}_3\text{CONH}_2 + 4[\text{H}] \xrightarrow{\text{LiAlH}_4/\text{ether}} \text{CH}_3\text{CH}_2\text{NH}_2 + \text{H}_2\text{O}$
In this process, the carbonyl oxygen is removed as a water molecule, which consumes two hydrogen atoms. The carbonyl carbon is reduced to a methylene group ($\text{CH}_2$), which consumes another two hydrogen atoms.
Thus, a total of $4$ moles of hydrogen atoms are required to reduce one mole of acetamide to one mole of ethanamine.
Answer: $4$
$\text{CH}_3\text{CONH}_2 + 4[\text{H}] \xrightarrow{\text{LiAlH}_4/\text{ether}} \text{CH}_3\text{CH}_2\text{NH}_2 + \text{H}_2\text{O}$
In this process, the carbonyl oxygen is removed as a water molecule, which consumes two hydrogen atoms. The carbonyl carbon is reduced to a methylene group ($\text{CH}_2$), which consumes another two hydrogen atoms.
Thus, a total of $4$ moles of hydrogen atoms are required to reduce one mole of acetamide to one mole of ethanamine.
Answer: $4$
Hence, the correct answer is option: 'A'.